fix: typo fixes

tex/3.11.tex

@@ -114,7 +114,7 @@
 	\subsection{(a)}
 
 	Want to show
-	\item \begin{equation}
+	\begin{equation}
 		\left. \pdv{T}{V} \right|_{S, N} = - \left. \pdv{P}{S} \right|_{V, N}
 	\end{equation}
 	
@@ -133,7 +133,7 @@
 		\pdv{T}{V_{S, N}} &= - \pdv{P}{S_{V, N}}
 	\end{align}
 
-	\subection{(b)}
+	\subsection{(b)}
 	
 	We want:
 	\begin{equation}

tex/3.8.tex

@@ -107,7 +107,7 @@
 
 	The equipartition theorem tells us that each degree of freedom in the kinetic energy should satisfy $\frac12 N \kb T$.
 	So, using the three degrees of freedom as described above, we can just write that $K = \left< E_1 \right> = \frac32 N \kb T$.
-	Our specific heat per particle satisfies $\N c_v^{(1)}) \left.\left( \pdv{E_1}{T} \right)\right|_{V, N}$, which is clearly $c_v^{(1)} = \frac32 \kb$, as Sethna wants us to find.
+	Our specific heat per particle satisfies $N c_v^{(1)} = \left.\left( \pdv{E_1}{T} \right)\right|_{V, N}$, which is clearly $c_v^{(1)} = \frac32 \kb$, as Sethna wants us to find.
 	
 	Now lets use \cref{eq:3} and solve for $c_v^{(2)}$.
 	\begin{align}